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4.Moving Charges and Magnetism
medium
A particle with ${10^{ - 11}}\,coulomb$ of charge and ${10^{ - 7}}\,kg$ mass is moving with a velocity of ${10^8}\,m/s$ along the $y$-axis. A uniform static magnetic field $B = 0.5\,Tesla$ is acting along the $x$-direction. The force on the particle is
A
$5 \times {10^{ - 11}}\,N$ along $\hat i$
B
$5 \times {10^3}\,N$ along $\hat k$
C
$5 \times {10^{ - 11}}\,N$ along $ - \hat j$
D
$5 \times {10^{ - 4}}\,N$ along $ - \hat k$
Solution
(d) $\overrightarrow F = q\,(\overrightarrow {v\,} \times \overrightarrow B ) = {10^{ – 11}}({10^8}\hat j\, \times 0.5\hat i)$
$ = 5 \times {10^{ – 4}}(\hat j \times \hat i) = 5 \times {10^{ – 4}}N( – \hat k)$
Standard 12
Physics
