A charged particle initially at rest at $O$,when released follows a trajectory as shown alongside. Such a trajectory is possible in the presence of
electric field of constant magnitude and varying direction
magnetic field of constant magnitude and varying direction
electric field of constant magnitude and constant direction
electric and magnetic fields of constant magnitudes and constant directions which are parallel to each other
An electron is projected normally from the surface of a sphere with speed $v_0$ in a uniform magnetic field perpendicular to the plane of the paper such that its strikes symmetrically opposite on the sphere with respect to the $x-$ axis. Radius of the sphere is $'a'$ and the distance of its centre from the wall is $'b'$ . What should be magnetic field such that the charge particle just escapes the wall
A moving charge will gain energy due to the application of
If the direction of the initial velocity of the charged particle is perpendicular to the magnetic field, then the orbit will be or The path executed by a charged particle whose motion is perpendicular to magnetic field is
In a region, steady and uniform electric and magnetic fields are present. These two fields are parallel to each other. A charged particle is released from rest in this region. The path of the particle will be a
A proton is projected with a velocity $10^7\, m/s$, at right angles to a uniform magnetic field of induction $100\, mT$. The time (in second) taken by the proton to traverse $90^o$ arc is $(m_p = 1.65\times10^{-27}\, kg$ and $q_p = 1.6\times10^{-19}\, C)$