A pendulum of length 2 m consists of a wooden bob of mass 50 g . A bullet of mass 75 g is fired towa

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5.Work, Energy, Power and Collision

hard

A pendulum of length $2 \; m$ consists of a wooden bob of mass $50 \; g$. A bullet of mass $75 \; g$ is fired towards the stationary bob with a speed $v$. The bullet emerges out of the bob with a speed $\frac{v}{3}$ and the bob just completes the vertical circle. The value of $v$ is $\dots \; ms ^{-1}$. (if $g =10 \; m / s ^{2}$ )

A

$08$

B

$09$

C

$10$

D

$11$

(JEE MAIN-2022)

Solution

Considering Only Horizontal direction

$(75 v)+0=50(\sqrt{5 g R})+75 \frac{v}{3}$

$75\left(v-\frac{v}{3}\right)=50 \sqrt{100}$

$v=10 \; m / s$

Standard 11

Physics

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