The bob of a simple pendulum is of mass $10\, gm$. It is suspended with a thread of $1\, m$. If we hold the bob so as to stretch the string horizontally and release it. What will be the tension at the lowest position   ……… $N$

A pendulum of length $2 \; m$ consists of a wooden bob of mass $50 \; g$. A bullet of mass $75 \; g$ is fired towards the stationary bob with a speed $v$. The bullet emerges out of the bob with a speed $\frac{v}{3}$ and the bob just completes the vertical circle. The value of $v$ is $\dots \; ms ^{-1}$. (if $g =10 \; m / s ^{2}$ )

A stone tied to a string of length $L$ is whirled in a vertical circle with the other end of the string at the centre. At a certain instant of time, the stone is at its lowest position and has a speed $u$. The magnitude of the change in its velocity as it reaches a position where the string is horizontal is

Two identical balls are interconnected with a massless and inextensible thread. The system is in gravity free space with the thread just taut. Each ball is imparted a velocity $v$, one towards the other ball and the other perpendicular to the first, at $t = 0$. Then,

In a simple pendulum, the breaking strength of the string is double the weight of the bob. The bob is released from rest when the string is horizontal. The string breaks when it makes an angle $\theta $ with the vertical