A person is standing on an open car moving with a constant velocity of $30\,\,m/s$ on a straight horizontal road. The man throws a ball in the vertically upward direction and it returns to the person after the car has moved $240\,\,m.$ The speed and the angle of projection
as seen from the car is $40\,\,m/s,\,\, 90^o$
as seen from the road is $50\,\,m/s,\,\,tan^{-1}\,\,(4/3)$
both $(A)$ and $(B)$
none
Two objects are projected with same velocity ' $u$ ' however at different angles $\alpha$ and $\beta$ with the horizontal. If $\alpha+\beta=90^{\circ}$, the ratio of horizontal range of the first object to the $2^{\text {nd }}$ object will be :
A ball thrown by a boy is caught by another after $2\ sec$. some distance away in the same level. If the angle of projection is $30^o $, the velocity of projection is ......... $m/s$
At the top of the trajectory of a projectile, the acceleration is
A projectile fired with initial velocity $u$ at some angle $\theta $ has a range $R$. If the initial velocity be doubled at the same angle of projection, then the range will be
A projectile is launched at an angle ' $\alpha$ ' with the horizontal with a velocity $20 \; ms ^{-1}$. After $10 s$, its inclination with horizontal is ' $\beta$ '. The value of $\tan \beta$ will be : $\left( g =10 \; ms ^{-2}\right)$