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11.Dual Nature of Radiation and matter
medium
A photon of wavelength $6630 \ Å$ is incident on a totally reflecting surface. The momentum delivered by the photon is equal to
A
$6.63 × 10^{-27} kg-m/sec$
B
$2 ×10^{-27} kg-m/sec$
C
$10^{-27} kg-m/sec$
D
None of these
Solution
(b)The momentum of the incident radiation is given as $p = \frac{h}{\lambda }$.
When the light is totally reflected normal to the surface the direction of the ray is reversed.
That means it reverses the direction of it’s momentum without changing it’s magnitude
$\therefore \Delta p = 2p = \frac{{2h}}{\lambda } = \frac{{2 \times 6.6 \times {{10}^{ – 34}}}}{{6630 \times {{10}^{ – 10}}}}= 2 × 10^{-27} kg-m/sec.$
Standard 12
Physics
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