The number of photons per second on an averag | vedclass

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Question

$\mathrm{p}=\frac{\mathrm{nhc}}{\lambda} \Rightarrow \mathrm{n}=\frac{\mathrm{p} \lambda}{\mathrm{hc}}$

$\mathrm{n}=\frac{3.3 	imes 10^{-3} 	imes

Vedclass · Accepted Answer

$10^{16}$

Vedclass · Answer

$\mathrm{p}=\frac{\mathrm{nhc}}{\lambda} \Rightarrow \mathrm{n}=\frac{\mathrm{p} \lambda}{\mathrm{hc}}$

$\mathrm{n}=\frac{3.3 	imes 10^{-3} 	imes 600 	imes 10^{-9}}{6.6 	imes 10^{-34} 	imes 3 	imes 10^{8}}=10^{16}$

The number of photons per second on an average emitted by the source of monochromatic light of wavelength $600\, \mathrm{~nm}$, when it delivers the power of $3.3 \times 10^{-3}$ $watt$ will be : $\left(\mathrm{h}=6.6 \times 10^{-34}\, \mathrm{Js}\right)$

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