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11.Dual Nature of Radiation and matter
medium
The number of photons per second on an average emitted by the source of monochromatic light of wavelength $600\, \mathrm{~nm}$, when it delivers the power of $3.3 \times 10^{-3}$ $watt$ will be : $\left(\mathrm{h}=6.6 \times 10^{-34}\, \mathrm{Js}\right)$
A
$10^{18}$
B
$10^{17}$
C
$10^{16}$
D
$10^{15}$
(NEET-2021)
Solution
$\mathrm{p}=\frac{\mathrm{nhc}}{\lambda} \Rightarrow \mathrm{n}=\frac{\mathrm{p} \lambda}{\mathrm{hc}}$
$\mathrm{n}=\frac{3.3 \times 10^{-3} \times 600 \times 10^{-9}}{6.6 \times 10^{-34} \times 3 \times 10^{8}}=10^{16}$
Standard 12
Physics
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