A point charge of +,12 ,μ C is at a distance 6 ,cm vertically above centre of a square of side 12,

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1. Electric Charges and Fields

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A point charge of $+\,12 \,\mu C$ is at a distance $6 \,cm$ vertically above the centre of a square of side $12\, cm$ as shown in figure. The magnitude of the electric flux through the square will be ....... $\times 10^{3} \,Nm ^{2} / C$

A

$452$

B

$381$

C

$226$

D

$113$

(JEE MAIN-2021)

Solution

From symmetry $\phi=\frac{1}{6}\left(\frac{ q }{\varepsilon_{0}}\right)$

$=\frac{12 \times 10^{-6}}{6 \times 8.85 \times 10^{-12}}$

$=225.98 \times 10^{3} \,\frac{ Nm ^{2}}{ s }$

$\simeq 226 \times 10^{3} \, \frac{ Nm ^{2}}{ C }$

Standard 12

Physics

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