Gujarati
11.Thermodynamics
medium

A polyatomic gas $\left( {\gamma = \frac{4}{3}} \right)$ is compressed to $\frac{1}{8}$ of its volume adiabatically. If its initial pressure is ${P_o}$, its new pressure will be

A

$8{P_o}$

B

$16{P_0}$

C

$6{P_o}$

D

$2{P_o}$

Solution

(b)$\frac{{{P_2}}}{{{P_1}}} = {\left( {\frac{{{V_1}}}{{{V_2}}}} \right)^\gamma }$==> ${P_2} = {P_1}{\left( {\frac{{{V_1}}}{{{V_2}}}} \right)^\gamma } = {P_0}{(8)^{4/3}} = 16{P_0}.$

Standard 11
Physics

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