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11.Thermodynamics
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A polyatomic gas $\left( {\gamma = \frac{4}{3}} \right)$ is compressed to $\frac{1}{8}$ of its volume adiabatically. If its initial pressure is ${P_o}$, its new pressure will be
A
$8{P_o}$
B
$16{P_0}$
C
$6{P_o}$
D
$2{P_o}$
Solution
(b)$\frac{{{P_2}}}{{{P_1}}} = {\left( {\frac{{{V_1}}}{{{V_2}}}} \right)^\gamma }$==> ${P_2} = {P_1}{\left( {\frac{{{V_1}}}{{{V_2}}}} \right)^\gamma } = {P_0}{(8)^{4/3}} = 16{P_0}.$
Standard 11
Physics
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