A projectile A is thrown at an angle 30^{circ} to horizontal from point P . At same time another pro

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3-2.Motion in Plane

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A projectile $A$ is thrown at an angle $30^{\circ}$ to the horizontal from point $P$. At the same time another projectile $B$ is thrown with velocity $v_2$ upwards from the point $Q$ vertically below the highest point $A$ would reach. For $B$ to collide with $A$, the ratio $\frac{v_2}{v_1}$ should be

A

$\frac{\sqrt{3}}{2}$

B

$2$

C

$\frac{1}{2}$

D

$\frac{2}{\sqrt{3}}$

Solution

(c)

Vertical component of velocity of $A$ should be equal to vertical velocity of $B$.

or $\quad v_1 \sin 30^{\circ}=v_2$

or $\frac{v_1}{2}=v_2$

$\therefore \quad \frac{v_2}{v_1}=\frac{1}{2}$

Standard 11

Physics

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