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Question

Ball performs parabolic motion,

For vertical motion,

$s = ut -\frac{1}{2} g t ^2$

$	herefore o =10 \sin 60^{\circ} t -\frac{1}{2} 	imes 10

Vedclass · Accepted Answer

$5$

Vedclass · Answer

Ball performs parabolic motion,

For vertical motion,

$s = ut -\frac{1}{2} g t ^2$

$	herefore o =10 \sin 60^{\circ} t -\frac{1}{2} 	imes 10 	imes t ^2$

$	herefore t =\sqrt{3} s$

For horizontal motion,

$s=u t+\frac{1}{2} a t^2$

$	herefore 1.15=10 \cos 60^{\circ} 	imes \sqrt{3}-\frac{1}{2} a (3)$

$	herefore a=5 \ m / s ^2$

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