A projectile is fired at 30^{circ} to horizontal, vertical component of its velocity is 80 ms ^{-1}

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3-2.Motion in Plane

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A projectile is fired at $30^{\circ}$ to the horizontal, The vertical component of its velocity is $80 \;ms ^{-1}$, Its time flight is $T$. What will be the velocity of projectile at $t =\frac{ T }{2}$?

A

$80\, ms^{-1}$

B

$80\sqrt 3 ms^{-1}$

C

$(80/\sqrt 3 ) ms^{-1}$

D

$40\, ms^{-1}$

Solution

$u_{vertical} = u\sin \theta = 80$

$\Rightarrow \,u = \frac{{80}}{{\sin {{30}^o}}} = 160\,m/s$

${u_{horizontal}} = u\cos \theta = 160\,\,\cos {30^o} = 80\sqrt 3 \,m/s.$

Standard 11

Physics

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