A projectile is fired from horizontal ground | vedclass

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Question

(image)

$d=\frac{v^2 \sin 2 	heta}{g}$

(image)

$H _{\operatorname{mex}}=\frac{ v ^2 \sin ^2 	heta}{2 g } ; \frac{1}{2} g _{ aff } t ^2= H _

Vedclass · Accepted Answer

$0.95$

Vedclass · Answer

(image)

$d=\frac{v^2 \sin 2 	heta}{g}$

(image)

$H _{\operatorname{mex}}=\frac{ v ^2 \sin ^2 	heta}{2 g } ; \frac{1}{2} g _{ aff } t ^2= H _{\max } \Rightarrow t ^2=\frac{2 H _{\max }}{ g _{ af }} ; t =\sqrt{\frac{ v ^2 \sin ^2 	heta 	imes 0.81}{g^2}} ; t =\frac{0.9 v \sin 	heta}{ g }$

$t ^2=\frac{2 	imes v ^2 \sin ^2 	heta}{2 g \left(\frac{ g }{0.81}ight)}$

$d ^{\prime}=	ext { New range }=\frac{d}{2}+ d _1$

$d _1= v \cos 	heta^{\circ} t$

$=\frac{ v ^2 \sin ^2 	heta \cos 	heta 	imes 0.9}{ g } ; d ^{\prime}=\frac{ v ^2 \sin 2 	heta}{2 g }+\frac{ v ^2 \sin 2 	heta 	imes 0.9}{2 g }$

$=\frac{ v ^2 \sin 2 	heta}{ g }\left(\frac{1.0}{2}ight)=0.95 d$

$n =0.95$

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