A projectile is projected with speed u of an angle of 60^o with horizontal from foot of an

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3-2.Motion in Plane

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A projectile is projected with speed $u$ of an angle of $60^o$ with horizontal from the foot of an inclined plane. If the projectile hits the inclined plane horizontally, the range on inclined plane will be :-

A

$\frac{u^2 \sqrt{21}}{2g}$

B

$\frac{3u^2}{4g}$

C

$\frac{u^2}{8g}$

D

$\frac{\sqrt {21}}{8} \frac{u^2}{g}$

Solution

Range on the inclined plane

$=\sqrt{\mathrm{h}_{\max }^{2}+\left(\frac{\mathrm{R}}{2}\right)^{2}}=\frac{\mathrm{u}^{2}}{\mathrm{g}} \frac{\sqrt{21}}{8}$

Standard 11

Physics

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