A radio can tune in to any station in the $7.5\; MHz$ to $12\; MHz$ band. What is the corresponding wavelength band?
A radio can tune in to any station in the $7.5\; MHz$ to $12\; MHz$ band. What is the corresponding wavelength band?
A radio can tune to minimum frequency, $v_{1}=7.5 MHz =7.5 \times 10^{6} Hz$
Maximum frequency, $v_{2}=12 MHz =12 \times 10^{6} Hz$
Speed of light, $c=3 \times 10^{8} m / s$
Corresponding wavelength for $v_{1}$ can be calculated as:
$\lambda_{1}=\frac{c}{v_{1}}$
$=\frac{3 \times 10^{8}}{7.5 \times 10^{6}}=40 m$
Corresponding wavelength for $v_{2}$ can be calculated as
$\lambda_{2}=\frac{c}{v_{2}}$
$=\frac{3 \times 10^{8}}{12 \times 10^{6}}=25 m$
Thus, the wavelength band of the radio is $40 m$ to $25 m$.
Similar Questions
Figure given shows the face of a cathode-ray oscilloscope tube, as viewed from in front. $i.e.$ the electron beam is coming out normally from the plane of the paper. The electron beam passes through a region where there are electric and magnetic fields directed as shown. The deflections of the spot from the center of the screen produced by the electric field $E$ and the magnetic field $B$ separately are equal in magnitude. Which one of the diagrams below shows a possible position of the spot on the screen when both fields are operating?
Figure given shows the face of a cathode-ray oscilloscope tube, as viewed from in front. $i.e.$ the electron beam is coming out normally from the plane of the paper. The electron beam passes through a region where there are electric and magnetic fields directed as shown. The deflections of the spot from the center of the screen produced by the electric field $E$ and the magnetic field $B$ separately are equal in magnitude. Which one of the diagrams below shows a possible position of the spot on the screen when both fields are operating?
Light wave is travelling along $y-$ direction. If the corresponding $\vec E$ vector at any time is along the $x-$ axis, the direction of $\vec B$ vector at that time is along
Light wave is travelling along $y-$ direction. If the corresponding $\vec E$ vector at any time is along the $x-$ axis, the direction of $\vec B$ vector at that time is along
A plane electromagnetic wave propagating in $\mathrm{x}$-direction is described by
$\mathrm{E}_{\mathrm{y}}=\left(200\ \mathrm{Vm}^{-1}\right) \sin \left[1.5 \times 10^7 \mathrm{t}-0.05\ \mathrm{x}\right] \text {; }$
The intensity of the wave is :(Use $\epsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}$ )
A plane electromagnetic wave propagating in $\mathrm{x}$-direction is described by
$\mathrm{E}_{\mathrm{y}}=\left(200\ \mathrm{Vm}^{-1}\right) \sin \left[1.5 \times 10^7 \mathrm{t}-0.05\ \mathrm{x}\right] \text {; }$
The intensity of the wave is :(Use $\epsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}$ )
- [JEE MAIN 2024]
The oscillating magnetic field in a plane electromagnetic wave is given by $B _{ y }=5 \times 10^{-6} \sin$ $1000\,\pi\left(5 x -4 \times 10^{8} t \right) T$. The amplitude of electric field will be.
The oscillating magnetic field in a plane electromagnetic wave is given by $B _{ y }=5 \times 10^{-6} \sin$ $1000\,\pi\left(5 x -4 \times 10^{8} t \right) T$. The amplitude of electric field will be.
- [JEE MAIN 2022]
A plane electromagnetic wave of wave intensity $6\,W/m^2$ strike a small mirror of area $30\,cm^2$ , held perpendicular to a approching wave. The momentum transmitted in $kg\, m/s$ by the wave to the mirror each second will be
A plane electromagnetic wave of wave intensity $6\,W/m^2$ strike a small mirror of area $30\,cm^2$ , held perpendicular to a approching wave. The momentum transmitted in $kg\, m/s$ by the wave to the mirror each second will be