A radioactive element ThA (_{84}Po^{216}) can | vedclass

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Question

${\lambda _{	ext{1}}} = \frac{{0.693}}{{{T_1}}}$

${\lambda _2} = \frac{{0.693}}{{{T_2}}}$

${\lambda _{eq}} = {\lambda _1} + {\lambda _2} = 0.69

Vedclass · Accepted Answer

$\frac{{{T_1}{T_2}}}{{{T_1} + {T_2}}}$

Vedclass · Answer

${\lambda _{	ext{1}}} = \frac{{0.693}}{{{T_1}}}$

${\lambda _2} = \frac{{0.693}}{{{T_2}}}$

${\lambda _{eq}} = {\lambda _1} + {\lambda _2} = 0.693\,/{T_{1/2}}$

${{	ext{T}}_{{	ext{1/2}}\,{	ext{eq}}{	ext{.}}}} = \frac{{{T_1}{T_2}}}{{{T_1} + {T_2}}}$

A radioactive element $ThA (_{84}Po^{216})$ can undergo $\alpha$ and $\beta$ are type of disintegrations with half-lives, $T_1$ and $T_2$ respectively. Then the half-life of ThA is

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