A radioactive nucleus is being produced at a constant rate α per second. Its decay constant is λ&n

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13.Nuclei

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A radioactive nucleus is being produced at a constant rate $\alpha$ per second. Its decay constant is $\lambda $. If $N_0$ are the number of nuclei at time $t = 0$, then maximum number of nuclei possible are

A

$\frac{\alpha }{\lambda }$

B

${N_0} + \frac{\alpha }{\lambda }$

C

$N_0$

D

$\frac{\lambda }{\alpha } + {N_0}$

Solution

(a) Maximum number of nuclei will be present when rate of decay = rate of formation

==> $\lambda N = \alpha $

==> $N = \frac{\alpha }{\lambda }$

Standard 12

Physics

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