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13.Nuclei
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The half-life of a radioactive substance is $30$ minutes. The times (in minutes ) taken between $40\%$ decay and $85\%$ decay of the same radioactive substance is
A
$45$
B
$60$
C
$15$
D
$30$
(NEET-2016)
Solution
$N_{0}=$ Nuclei at time $t=0$
$N_{\mathrm{1}}=$ Remaining nuclei after $40 \%$ decay
$=(1-0.4) N_{0}=0.6 N_{0}$
$N_{2}=$ Remaining nuclei after $85 \%$ decay
$=(1-0.85) N_{0}=0.15 N_{0}$
$\therefore$ $\frac{N_{2}}{N_{1}}=\frac{0.15 N_{0}}{0.6 N_{0}}=\frac{1}{4}=\left(\frac{1}{2}\right)^{2}$
Hence, two half life is required between $40 \%$ decay and $85 \%$ decay of a radioactive substance.
$\therefore$ Time taken $=2 \tau_{1 / 2}=2 \times 30 \mathrm{min}=60 \mathrm{min}$
Standard 12
Physics
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