A real gas behaves like an ideal gas if its

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12.Kinetic Theory of Gases

normal

A real gas behaves like an ideal gas if its

pressure and temperature are both high

pressure and temperature are both low

pressure is high and temperature is low

pressure is low and temperature is high

Solution

By real gas equation, $\left(P+\frac{a}{V^{2}}\right)(V-b)=R T$

At High $T,$ the gas molecules have a higher average kinetic energy $(KEavg)$ which overcomes the $IMF$( (Intermoleculer force) At Low $P.$ , the gas molecules are spread further apart and can therefore avoid $IMF$. So, pressure should be low and temperature should be high for the ideal gas behaviour

Standard 11

Physics

Two containers of equal volume contain the same gas at pressure $P_1$ and $P_2$ and absolute temperature $T_1$ and $T_2$ respectively. On joining the vessles, the gas reaches a common pressure $P$ and common temperature $T$. The ratio $P/T$ is equal to

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Figure shows the volume versus temperature graph for the same mass of a gas (assumed ideal) corresponding to two different pressures $P_1$ and $P_2$. Then,

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A vessel is partitioned in two equal halves by a fixed diathermic separator. Two different ideal gases are filled in left $(L)$ and right $(R)$ halves. The $rms$ speed of the molecules in $L$ part is equal to the mean speed of molecules in the $R$ part. Then the ratio of the mass of a molecules in $L$ part to that of a molecules in $R$ part is

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The ratio $C_P /C_V$ for a gas mixture consisting of $8\,g$ of helium and $16\,g$ of oxygen is

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The average translational energy and the rms speed of molecules of a sample of oxygen gas at $300\ K$ are $6.21 \times 10^{-21}\ J$ and $484\ m/s$ respectively. The corresponding values at $600\ K$ are nearly (assuming ideal gas behaviour)

normal

A real gas behaves like an ideal gas if its

Solution

Similar Questions

Two containers of equal volume contain the same gas at pressure $P_1$ and $P_2$ and absolute temperature $T_1$ and $T_2$ respectively. On joining the vessles, the gas reaches a common pressure $P$ and common temperature $T$. The ratio $P/T$ is equal to

Figure shows the volume versus temperature graph for the same mass of a gas (assumed ideal) corresponding to two different pressures $P_1$ and $P_2$. Then,

The ratio $C_P /C_V$ for a gas mixture consisting of $8\,g$ of helium and $16\,g$ of oxygen is

The average translational energy and the rms speed of molecules of a sample of oxygen gas at $300\ K$ are $6.21 \times 10^{-21}\ J$ and $484\ m/s$ respectively. The corresponding values at $600\ K$ are nearly (assuming ideal gas behaviour)

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