A rod of length 1,meter is standing vertically, when its other end touches ground without slipping t

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6.System of Particles and Rotational Motion

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A rod of length $1\,meter$ is standing vertically, when its other end touches the ground without slipping then the speed of other end will be

A

$\sqrt {19\times 6}\,m/sec$

B

$\sqrt {29\times 4}\,m/sec$

C

$\sqrt {9.8\times 3}\,m/sec$

D

$9·8\, m/sec$

Solution

By energy conservation law

$\frac{m g \ell}{2}+0=0+\frac{1}{2} \frac{m \ell^{2}}{3} \omega^{2}$

$\omega=\sqrt{\frac{3 g}{\ell}}=\sqrt{3 \times 9.8}$

$\mathrm{v}=\omega \mathrm{r}=\sqrt{3 \times 9.8} \mathrm{m} / \mathrm{s}$

Standard 11

Physics

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