A running man has half the kinetic energy of that of a boy of half of his mass. The man speeds up by $1\,m/s$ so as to have same K.E. as that of the boy. The original speed of the man will be
$\sqrt 2 \,m/s$
$(\sqrt 2 - 1)\,m/s$
$\frac{1}{{(\sqrt 2 - 1)}}m/s$
$\frac{1}{{\sqrt 2 }}m/s$
Two solids $A$ and $B$ of mass $1\, kg$ and $2\, kg$ respectively are moving with equal linear momentum. The ratio of their kinetic energies $(K.E.)_{ A }:( K.E. )_{ B }$ will be $\frac{ A }{1},$ so the value of $A$ will be ..... .
Two bodies $A$ and $B$ having masses in the ratio of $3 : 1$ possess the same kinetic energy. The ratio of their linear momenta is then
Two masses of $1 \,gm$ and $4 \,gm$ are moving with equal kinetic energies. The ratio of the magnitudes of their linear momenta is
Four particles given, have same momentum which has maximum kinetic energy
The kinetic energy acquired by a mass $m$ in travelling a certain distance $d$ starting from rest under the action of a constant force is directly proportional to