A student measured length of a rod and wrote it as 3.50cm . Which instrument did he use to measure i

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1.Units, Dimensions and Measurement

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A student measured the length of a rod and wrote it as $3.50\;cm$. Which instrument did he use to measure it?

A

A vernier calliper where the $10$ divisions in vernier scale matches with $9$ division in main scale and main scale has $10$ divisions in $1\; cm$.

B

A screw gauge having $100$ divisions in the circular scale and pitch as $1\; mm.$

C

A screw gauge having $50$ divisions in the circular scale and pitch as $1\; mm.$

D

A meter scale.

(JEE MAIN-2014)

Solution

If student measures $3.50 \mathrm{cm},$ it means that there is an uncertainly of order $0.01 \mathrm{cm} .$

For vernier scale with $1 \mathrm{MSD}=\frac{1}{10} \mathrm{cm}$ and $9 \mathrm{MSD}=10 \mathrm{VSD}$

$LC$ of vernier calliper $=1 \mathrm{MSD}-1 \mathrm{VSD}$

$=\frac{1}{10}\left(1-\frac{9}{10}\right)=\frac{1}{100} \mathrm{cm}=0.01 \mathrm{cm}$

Standard 11

Physics

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