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7.Profit and Loss
medium
A shopkeeper cheats to the extent of $10 \%$ while buying as well as selling, by using false weights. His total gain is in $\%$
A
$10$
B
$11$
C
$20$
D
$21$
Solution
The shopkeeper pays for $900$ $g$ instead of $1000$ $g$ while buying and sells the item weighing $900 gm$ for $1000 g$ or $1 kg$
$\operatorname{Gain} \%=\frac{(100+\operatorname{common} gain \%)^{2}}{100}-100$
$=\left[\frac{(100+10)^{2}}{100}-100\right] \%$
$=\left[\frac{12100}{100}-100\right] \%=21 \%$
Standard 13
Quantitative Aptitude