A short bar magnet with its north pole facing north forms a neutral point at $P$ in the horizontal plane. If the magnet is rotated by $90^o$ in the horizontal plane, the net magnetic induction at $P$ is (Horizontal component of earth’s magnetic field = ${B_H}$)

  • A

    $0$

  • B

    $2 BH$

  • C

    $\frac{{\sqrt 5 }}{2}{B_H}$

  • D

    $\sqrt 5 \,{B_H}$

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