A short magnet of moment $6.75\, Am^2$ produces a neutral point on its axis. If horizontal component of earth's magnetic field is $5 \times {10^{ - 5}}\,Wb/{m^2}$, then the distance of the neutral point should be.....$cm$

  • A

    $10$

  • B

    $20$

  • C

    $30$

  • D

    $40$

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