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5.Magnetism and Matter
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The distance between the poles of a horse shoe magnet is $0.1\, m$ and its pole strength is $0.01\, amp-m$. The induction of magnetic field at a point midway between the poles will be
A
$2 \times {10^{ - 5}}\,T$
B
$4 \times {10^{ - 6}}\,T$
C
$8 \times {10^{ - 7}}\,T$
D
Zero
Solution
(c) Net magnetic field at mid point $P$,$B = {B_N} + {B_S}$
where ${B_N} = $ magnetic field due to $N$ – pole
${B_S} = $ magnetic field due to $S$ – pole
${B_N} = {B_S} = \frac{{{\mu _0}}}{{4\pi }}\frac{m}{{{r^2}}}$
$ = {10^{ – 7}} \times \frac{{0.01}}{{{{\left( {\frac{{0.1}}{2}} \right)}^2}}} = 4 \times {10^{ – 7}}\,T$
$\therefore {B_{net}} = 8 \times {10^{ – 7}}\,T.$
Standard 12
Physics
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