A simple pendulum hanging from ceiling of a stationary lift has a time period T₁ . When lift moves

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13.Oscillations

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A simple pendulum hanging from the ceiling of a stationary lift has a time period $T_1$. When the lift moves downward with constant velocity, the time period is $T_2$, then

A

${T_2}$ is infinity

B

${T_2} = {T_1}$

C

${T_2} < {T_1}$

D

${T_2} > {T_1}$

Solution

(b) $T\sqrt {\frac{l}{g}} $ and $g$ is same in both cases so time period remain same.

Standard 11

Physics

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