- Home
- Standard 11
- Physics
13.Oscillations
easy
A simple pendulum hanging from the ceiling of a stationary lift has a time period $T_1$. When the lift moves downward with constant velocity, the time period is $T_2$, then
A
${T_2}$ is infinity
B
${T_2} = {T_1}$
C
${T_2} < {T_1}$
D
${T_2} > {T_1}$
Solution
(b) $T\sqrt {\frac{l}{g}} $ and $g$ is same in both cases so time period remain same.
Standard 11
Physics
