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13.Oscillations
easy
A simple pendulum is taken from the equator to the pole. Its period
A
Decreases
B
Increases
C
Remains the same
D
Decreases and then increases
Solution
(a)As we go from equator to pole the value of g increases. Therefore time period of simple pendulum $\left( {T \propto \frac{1}{{\sqrt g }}} \right)$ decreases.
Standard 11
Physics
Similar Questions
In the following table relation of graph in column$-I$ and shape of graph in column$-II$ is shown match them appropriately.
column$-I$ | column $-II$ |
$(a)$ ${T^2} \to l$ | $(i)$ Linear |
$(b)$ ${T^2} \to g$ | $(ii)$ Parabolic |
$(c)$ ${T} \to l$ | $(iii)$ Hyperbolic |
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