A simple pendulum has time period T . bob is given negative charge and surface below it is given pos

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13.Oscillations

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A simple pendulum has time period $T$. The bob is given negative charge and surface below it is given positive charge. The new time period will be

A

Less than $T$

B

Greater than $T$

C

Equal to $T$

D

Infinite

Solution

(a) In this case time period of pendulum becomes
$T' = 2\pi \sqrt {\frac{l}{{\left( {g + \frac{{qE}}{m}} \right)}}} $
==> $T' < T$

Standard 11

Physics

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