A simple pendulum of mass 200, gm and length | vedclass

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Question

Reference level

(Here $\mathrm{m}=200 \mathrm{gm}$

$\mathrm{L}=100 \mathrm{cm}=1 \mathrm{m}$

$\left.g=10 m / \sec ^{2}\right)$

$\mathrm{W}

Vedclass · Accepted Answer

$7.174 	imes 10^6\, erg,\, 2.626 	imes 10^6\, erg$

Vedclass · Answer

Reference level

(Here $\mathrm{m}=200 \mathrm{gm}$

$\mathrm{L}=100 \mathrm{cm}=1 \mathrm{m}$

$\left.g=10 m / \sec ^{2}ight)$

$\mathrm{W}=\Delta \mathrm{k}$

$mgL\left( {\cos {{30}^\circ } - \cos {{60}^\circ }} ight) = K{E_f} - K{E_i}$

${m{K}}.{{m{E}}_f} = {m{mgL}}\left( {\cos {{30}^\circ } - \cos {{60}^\circ }} ight)$

$=0.732 \mathrm{J}$

$=7.32 	imes 10^{6} \mathrm{erg}$

$\mathrm{PE}=\mathrm{mgL}\left(1-\cos 30^{\circ}ight)$

$=0.268 \mathrm{J}$

$=2.68 	imes 10^{6} \mathrm{erg}$

A simple pendulum of mass $200\, gm$ and length $100\, cm$ is moved aside till the string makes an angle of $60^o$ with the vertical. The kinetic and potential energies of the bob, when the string is inclined at $30^o$ to the vertical, are

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