A small bar magnet has a magnetic moment $1.2 \,A-m^2$. The magnetic field at a distance $ 0.1\, m $ on its axis will be : ($\mu_0 = 4\pi \times 10^{-7} \,T-m/A$)

  • A

    $1.2 \times 10^{-4} \,T$

  • B

    $2.4 \times 10^{-4} \,T$

  • C

    $2.4 \times 10^{4} \,T$

  • D

    $1.2 \times 10^{4}\, T$

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  • [IIT 1982]