A small soap bubble of radius $4\,cm$ is trapped inside another bubble of radius $6\,cm$ without any contact. Let $P_2$ be the pressure inside the inner bubble and $P_0$ the pressure outside the outer bubble. Radius of another bubble with pressure difference $P_2 - P_0$ between its inside and outside would be....... $cm$
$6$
$12$
$4.8$
$2.4$
Pressure inside two soap bubbles are $1.01$ and $1.02$ atmosphere, respectively. The ratio of their volumes is
Two soap bubbles of radii ${r_1}$ and ${r_2}$ equal to $4 \,cm $ and $5 \,cm $ are touching each other over a common surface ${S_1}{S_2}$ (shown in figure). Its radius will be ....... $cm$
Pressure inside a soap bubble is greater than the pressure outside by an amount :
(given : $\mathrm{R}=$ Radius of bubble, $\mathrm{S}=$ Surface tension of bubble)
The excess pressure in a soap bubble is thrice that in other one. Then the ratio of their volume is
A capillary tube of radius $r$ is dipped in a liquid of density $\rho$ and surface tension $S$. If the angle of contact is $\theta$, the pressure difference between the two surfaces in the beaker and the capillary