Two soap bubbles of radii ${r_1}$ and ${r_2}$ equal to $4 \,cm $ and $5 \,cm $ are touching each other over a common surface ${S_1}{S_2}$ (shown in figure). Its radius will be ....... $cm$
$4$
$20$
$5$
$4.5$
Formation of bubble are in Column - $\mathrm{I}$ and pressure difference between them are given in Column - $\mathrm{II}$. Match them appropriately.
Column - $\mathrm{I}$ | Column - $\mathrm{II}$ |
$(a)$ Liquid drop in air | $(i)$ $\frac{{4T}}{R}$ |
$(b)$ Bubble of liquid in air | $(ii)$ $\frac{{2T}}{R}$ |
$(iii)$ $\frac{{2R}}{T}$ |
The excess pressure inside a soap bubble is thrice the excess pressure inside a second soap bubble. The ratio between the volume of the first and the second bubble is:
The surface tension and vapour pressure of water at $20^{°}$ $\mathrm{C}$ is $7.28 \times {10^{ - 2}}\,{\rm{N/m}}$ and $2.33 \times {10^3}\,{{\rm{P}}_{\rm{a}}}$ respectively. What is the radius of the smallest spherical water droplet which can form without evaporating at $20^{°}$ $\mathrm{C}$ ?
A soap bubble in vacuum has a radius of $3 \,cm$ and another soap bubble in vacuum has a radius of $4 \,cm$. If the two bubbles coalesce under isothermal condition, then the radius of the new bubble is ....... $cm$
If the radius of a soap bubble is four times that of another, then the ratio of their excess pressures will be