9-1.Fluid Mechanics
hard

A small sphere of radius $r$ falls from rest in a viscous liquid. As a result, heat is produced due to viscous force. The rate of production of heat when the sphere attains its terminal velocity, is proportional to

A

$r^3$

B

$\;$$r^2$

C

$r^4$

D

$\;$$r^5$

(NEET-2018)

Solution

The viscous drag force, $F = 6\pi \eta rv;$

$where\,v = terminal\,velocity$

$\therefore \,The\,rate\,of\,production\,of\,heat = power$

$ = force \times terminal\,velocity$

$ \Rightarrow power = 6\pi \eta rv \cdot v = 6\pi \eta r{v^2}\,\,\,\,\,\,\,\,…\left( i \right)$

$Terminal\,velocity\,v = \frac{{2{r^2}\left( {\rho  – \sigma } \right)}}{{9\eta }};\,\,\,\therefore v \propto {r^2}$

$Now,\,power = 6\pi \eta r\left[ {\frac{{4{r^2}{{\left( {\rho  – \sigma } \right)}^2}}}{{81{\eta ^2}}}{g^2}} \right]or\,power \propto {r^5}.$

Standard 11
Physics

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