A soap bubble of radius 3, {cm} is formed ins | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Excess pressure inside the smaller soap bubble

$\Delta {P}=\frac{4 {S}}{{r}_{1}}+\frac{4 {S}}{{r}_{2}}\ldots 	ext { (i) }$

The excess pressure

Vedclass · Accepted Answer

$2$

Vedclass · Answer

Excess pressure inside the smaller soap bubble

$\Delta {P}=\frac{4 {S}}{{r}_{1}}+\frac{4 {S}}{{r}_{2}}\ldots 	ext { (i) }$

The excess pressure inside the equivalent soap bubble

$\Delta {P}=\frac{4 {S}}{{R}_{{eq}}} \ldots 	ext { (ii) }$

From $ (i) \,\& \,(ii)$

$\frac{4 {S}}{{R}_{{eq}}}=\frac{4 {S}}{{T}_{1}}+\frac{4 {S}}{{T}_{2}}$

$\frac{1}{{R}_{{eq}}}=\frac{1}{{T}_{1}}+\frac{1}{{I}_{2}}$

$=\frac{1}{6}+\frac{1}{3}$

${R}_{{eq}}=2 \,{cm}$

A soap bubble of radius $3\, {cm}$ is formed inside the another soap bubble of radius $6\, {cm}$. The radius of an equivalent soap bubble which has the same excess pressure as inside the smaller bubble with respect to the atmospheric pressure is .......... ${cm}$

Similar Questions

There is a small hole in hollow sphere. Water enters in sphere when it is taken at depth of $40\,cm$ in water. Diameter of hole is ....... $mm$ (Surface tension of water $= 0.07\, N/m$):

The pressure of air in a soap bubble of $0.7\,cm$ diameter is $8\, mm$ of water above the pressure outside. The surface tension of the soap solution is ........ $dyne/cm$

There is small hole in a hollow sphere. The water enters in it when it is taken to a depth of $40 \,cm$ under water. The surface tension of water is $0.07 \,N / m$. The diameter of hole is .......... $mm$

Two soap bubbles of radii ${r_1}$ and ${r_2}$ equal to $4 \,cm $ and $5 \,cm $ are touching each other over a common surface ${S_1}{S_2}$ (shown in figure). Its radius will be ....... $cm$