There is small hole in a hollow sphere. The w | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b)

Let take $g=10 \,m / s ^2$

For water to enter the sphere, pressure required is $=ho g h$

$=1 	imes 10 	imes \frac{40}{100} 	imes 100

Vedclass · Accepted Answer

$0.07$

Vedclass · Answer

(b)

Let take $g=10 \,m / s ^2$

For water to enter the sphere, pressure required is $=ho g h$

$=1 	imes 10 	imes \frac{40}{100} 	imes 1000 \quad\left(ho=1000 \,kg / m ^3ight)$

$=4000 \,\frac{ N }{ m ^2}=	ext { excess pressure }$

Let the hole have radius $=R$

Excess pressure $=\frac{2 T}{R}$    [One surface air, one surface water]

$\Rightarrow 4000=\frac{2 	imes 0.07}{R}$

$\Rightarrow 2 R=0.07 	imes 10^{-3} \,m$

$\Rightarrow d=0.07 \,mm$

Column - $\mathrm{I}$	Column - $\mathrm{II}$
$(a)$ Liquid drop in air	$(i)$ $\frac{{4T}}{R}$
$(b)$ Bubble of liquid in air	$(ii)$ $\frac{{2T}}{R}$
	$(iii)$ $\frac{{2R}}{T}$

There is small hole in a hollow sphere. The water enters in it when it is taken to a depth of $40 \,cm$ under water. The surface tension of water is $0.07 \,N / m$. The diameter of hole is .......... $mm$

Similar Questions

A soap bubble in a form of circular tube having radius of curvature $R$ and radius of curvature perpendicular to it is $5R$ . Find the excess pressure in the bubble :

Derive the formula for excess of pressure (pressure difference) inside the drop and bubble.

If the radius of a soap bubble is four times that of another, then the ratio of their excess pressures will be

Two spherical soap bubbles formed in vacuum has diameter $3.0\,mm$ and $4.0\,mm$ . They coalesce to form a single spherical bubble. If the temperature remains unchanged, find the diameter of the bubble so formed ....... $mm$