A solid sphere rolls down without slipping on an inclined plane, then percentage of rotational

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6.System of Particles and Rotational Motion

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A solid sphere rolls down without slipping on an inclined plane, then percentage of rotational kinetic energy of total energy will be ........ $\%.$

A

$25$

B

$28.6$

C

$36$

D

$35$

Solution

$\frac{E_{r}}{E_{t}}=\frac{\frac{1}{2} I \omega^{2}}{\frac{1}{2} I \omega^{2}+\frac{1}{2} M V^{2}}$ and $V=\omega R$

Standard 11

Physics

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