A solution of weak acid $HA$ containing $0.01$ moles of acid per litre of solutions has $pH = 4$. The percentage degree of ionisation of the acid and the ionisation constant of acid are respectively.
$1\% ,\,{10^{ - 6}}$
$0.01\% ,\,{10^{ - 4}}$
$1\% ,\,{10^{ - 4}}$
$0.01\% ,\,{10^{ - 6}}$
Explain a general step-wise approach to evaluate the $pH$ of the weak electrolyte.
$pH$ of $0.1\,\, M$ $N{H_3}$ aqueous solution is $({K_b} = 1.8 \times {10^{ - 5}})$
Derive ${K_a} \times {K_b} = {K_w}$ equation.
For a weak acid, the incorrect statement is
Dissociation constant for a monobasic acid is $10^{-4}$ . What is the $pH$ of the monobasic acid ? (If $\%$ dissociation $= 2\,\%$ )