Gujarati
6-2.Equilibrium-II (Ionic Equilibrium)
medium

A solution of weak acid $HA$ containing $0.01$ moles of acid per litre of solutions has $pH = 4$. The percentage degree of ionisation of the acid and the ionisation constant of acid are respectively.

A

$1\% ,\,{10^{ - 6}}$

B

$0.01\% ,\,{10^{ - 4}}$

C

$1\% ,\,{10^{ - 4}}$

D

$0.01\% ,\,{10^{ - 6}}$

Solution

(a) ${H^ + } = C\alpha $

$\alpha = \frac{{{H^ + }}}{C} = \frac{{{{10}^{ – 4}}}}{{{{10}^{ – 2}}}} = {10^{ – 6}}$

Standard 11
Chemistry

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