A sperical ball of mass m=5,kg rests between | vedclass

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Question

$50+\frac{N_1}{\sqrt{2}}=\frac{N_2 \sqrt{3}}{2}$
$\frac{ N _1}{\sqrt{2}}=\frac{ N _2}{2}$
On solving we get
$N _1$ and $N _2$
$N _1=96.59\,N , N _

Vedclass · Accepted Answer

$N _{45}=96.59\,N , \quad N _{30}=136.6\,N$

Vedclass · Answer

$50+\frac{N_1}{\sqrt{2}}=\frac{N_2 \sqrt{3}}{2}$
$\frac{ N _1}{\sqrt{2}}=\frac{ N _2}{2}$
On solving we get
$N _1$ and $N _2$
$N _1=96.59\,N , N _2=136.6\,N$

A sperical ball of mass $m=5\,kg$ rests between two planes which make angles of $30^{\circ}$ and $45^{\circ}$ respectively with the horizontal. The system is in equilibrium. Find the normal forces exerted on the ball by each of the planes. The planes are smooth.

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