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5.Work, Energy, Power and Collision
medium
A spring when stretched by $2 \,mm$ its potential energy becomes $4 \,J$. If it is stretched by $10 \,mm$, its potential energy is equal to
A
$4 \,J$
B
$54 \,J$
C
$415\, J$
D
None
Solution
(d)$U = \frac{1}{2}k{x^2}$ if $x $ becomes $ 5$ times then energy will become $25 $ times i.e. $4 \times 25 = 100\,J$
Standard 11
Physics
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