Gujarati
5.Work, Energy, Power and Collision
medium

A spring when stretched by $2 \,mm$ its potential energy becomes $4 \,J$. If it is stretched by $10 \,mm$, its potential energy is equal to

A

$4 \,J$

B

$54 \,J$

C

$415\, J$

D

None

Solution

(d)$U = \frac{1}{2}k{x^2}$ if $x $ becomes $ 5$  times then energy will become $25 $ times i.e. $4 \times 25 = 100\,J$

Standard 11
Physics

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