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9-1.Fluid Mechanics
hard
A steel ball is dropped in a viscous liquid. The distance of the steel ball from the top of the liquid is shown below. The terminal velocity of the ball is closest to .......... $m/s$

A
$0.26$
B
$0.33$
C
$0.45$
D
$0.21$
(KVPY-2019)
Solution

(b)
Velocity $=$ Slope of distance – Time graph
Last portion of given graph is a straight line which indicates that velocity is constant, i.e. terminal velocity is reached.
From data of graph, Terminal velocity,
$v=\frac{x_2-x_1}{t_2-t_1}=0.4-0.3$
$=\frac{0.1}{0.3}=0.33 \,m / s$
Standard 11
Physics