Gujarati
9-1.Fluid Mechanics
hard

A steel ball is dropped in a viscous liquid. The distance of the steel ball from the top of the liquid is shown below. The terminal velocity of the ball is closest to .......... $m/s$

A

$0.26$

B

$0.33$

C

$0.45$

D

$0.21$

(KVPY-2019)

Solution

(b)

Velocity $=$ Slope of distance – Time graph

Last portion of given graph is a straight line which indicates that velocity is constant, i.e. terminal velocity is reached.

From data of graph, Terminal velocity,

$v=\frac{x_2-x_1}{t_2-t_1}=0.4-0.3$

$=\frac{0.1}{0.3}=0.33 \,m / s$

Standard 11
Physics

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