A steel rod of diameter $1\,cm$ is clamped firmly at each end when its temperature is $25\,^oC$ so that it cannot contract on cooling. The tension in the rod at $0\,^oC$ is approximately ......... $N$ $(\alpha = 10^{-5}/\,^oC,\,\,Y = 2 \times 10^{11}\,N/m^2)$
$4000$
$7000$
$7400$
$4700$
The coefficient of linear expansion of brass and steel are ${\alpha _1}$ and ${\alpha _2}$. If we take a brass rod of length ${l_1}$ and steel rod of length ${l_2}$ at $0°C$, their difference in length $({l_2} - {l_1})$ will remain the same at a temperature if
Two straight metallic strips each of thickness $t$ and length $\ell$ are rivetted together. Their coefficients of linear expansions are $\alpha_1$ and $\alpha_2$. If they are heated through temperature $\Delta T$, the bimetallic strip will bend to form an arc of radius
Two rods are joined between fixed supports as shown in the figure. Condition for no change in the lengths of individual rods with the increase of temperature will be
( ${\alpha _1},\,{\alpha _2},$ = linear expansion coefficient
$A_1, A_2$ = Area of rods
$Y_1, Y_2$ = Young modulus)
A brass disc fits simply in a hole of a steel plate. The disc from the hole can be loosened if the system
A solid metallic cube having total surface area $24\;m ^{2}$ is uniformly heated. If its temperature is increased by $10\,^{\circ} C$, calculate the increase in volume of the cube $\left(\right.$ Given $\left.: \alpha=5.0 \times 10^{-4}{ }^{\circ} C ^{-1}\right)$