A uniform cylindrical rod of length L and rad | vedclass

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Question

Lenght of cylinder remains unchanged

So ${\left( {\frac{F}{A}} \right)_{compressive}} = {\left( {\frac{F}{A}} \right)_{Themal}}$

$\frac{F}{

Vedclass · Accepted Answer

$3F/\left( {\pi {r^2}YT} \right)$

Vedclass · Answer

Lenght of cylinder remains unchanged

So ${\left( {\frac{F}{A}} ight)_{compressive}} = {\left( {\frac{F}{A}} ight)_{Themal}}$

$\frac{F}{{\pi {r^2}}} = Y\alpha T\,\,\,\,\,\,\left( {\alpha \,is\,liner\,coefficient\,of\,\exp ansion} ight)$

$	herefore \alpha  = \frac{F}{{YT\pi {r^2}}}$

$	herefore \,The\,coefficient\,of\,volume\,expansion\,\gamma  = 3\alpha $

$	herefore \gamma  =3 \frac{F}{{YT\pi {r^2}}}$

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