A stone falls from a balloon that is descending at a uniform rate of 12,,m/s . displacement of stone

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2.Motion in Straight Line

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A stone falls from a balloon that is descending at a uniform rate of $12\,\,m/s$. The displacement of the stone from the point of release after $10 \,sec$ is.......$m$

($g = 9.8\,m/{s^2}$)

A

$490$

B

$510$

C

$610 $

D

$725$

Solution

(c) $u = 12\;m/s$, $g = 9.8\;m/{\sec ^2}$, $t = 10\;\sec $

Displacement $ = ut + \frac{1}{2}g{t^2}$

$ = 12 \times 10 + \frac{1}{2} \times 9.8 \times 100 = 610\,m$

Standard 11

Physics

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