A stone is allowed to fall from top of a tower 100,,metre high and at same time another stone

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2.Motion in Straight Line

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A stone is allowed to fall from the top of a tower $100\,\,metre$ high and at the same time another stone is projected vertically upwards from the ground with a velocity of $25\,\,ms^{-1}.$ The two stones will meet after.........$s$

A

$4$

B

$0.4$

C

$0.04$

D

$40$

Solution

$\mathrm{S}_{1}+\mathrm{S}_{2}=100$

$\frac{1}{2} g t^{2}+\left[u t-\frac{1}{2} g t^{2}\right]=100$

$t=\frac{100}{u}=\frac{100}{25}=4 s$

Standard 11

Physics

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