A stone is projected from a point on the grou | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(d)

$2 h=\frac{u_y^2}{2 g}$

or $u_y=2(\sqrt{g} h)$

$\operatorname{Now}\left(t_2-t_1\right) u_x=t_2 v_x$ or $\frac{v_x}{u_x}=\frac{t_2-t_1}{t_

Vedclass · Accepted Answer

$\frac{2}{\sqrt{2}+1}$

Vedclass · Answer

(d)

$2 h=\frac{u_y^2}{2 g}$

or $u_y=2(\sqrt{g} h)$

$\operatorname{Now}\left(t_2-t_1\right) u_x=t_2 v_x$ or $\frac{v_x}{u_x}=\frac{t_2-t_1}{t_2}........(i)$

Further $h=u_y t-\frac{1}{2}(g t)^2$

or $g t^2-2 u_y t+h=0$

or $g t^2-4(\sqrt{g h}) t+2 h=0$

$t_1= \frac{4 \sqrt{g h}-\sqrt{16 g h-8 g h}}{2 g}=(2-\sqrt{2})\left(\frac{\sqrt{h}}{g}\right)$

Substituting in Eq. (i) we have,

$\frac{v_x}{u_x}=\frac{2}{(\sqrt{2})+1}$

Similar Questions

A shell fired from the base of a mountain just clears it. If $\alpha$ is the angle of projection then the angular elevation of the summit $\beta$ is

A particle projected from ground moves at angle $45^{\circ}$ with horizontal one second after projection and speed is minimum two seconds after the projection. The angle of projection of particle is [Neglect the effect of air resistance]

Two particles are projected from the same point with the same speed $u$ such that they have the same range $R$, but different maximum heights, $h_1$ and $h_2$. Which of the following is correct ?

If a stone is to hit at a point which is at a distance $d$ away and at a height $h$ above the point from where the stone starts, then what is the value of initial speed $u$ if the stone is launched at an angle $\theta $ ?

Two projectiles are projected at $30^{\circ}$ and $60^{\circ}$ with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is: