Gujarati
Hindi
3-2.Motion in Plane
medium

The maximum horizontal range of a projectile is $16\,km$ when the projectile is thrown at an elevation of $30^o$ from the horizontal, it will reach to the maximum height of ....... $km$

A

$2$

B

$4$

C

$8$

D

$16$

Solution

$\mathrm{R}=\frac{\mathrm{u}^{2} \sin 2 \theta}{\mathrm{g}}$ so that $\mathrm{R}_{\max }=\frac{\mathrm{u}^{2}}{\mathrm{g}}=16 \mathrm{km}$

$\mathrm{H}_{\max }=\frac{\mathrm{u}^{2} \sin ^{2} \theta}{2 \mathrm{g}}=2 \mathrm{km}$

Standard 11
Physics

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