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3-2.Motion in Plane
medium
The maximum horizontal range of a projectile is $16\,km$ when the projectile is thrown at an elevation of $30^o$ from the horizontal, it will reach to the maximum height of ....... $km$
A
$2$
B
$4$
C
$8$
D
$16$
Solution
$\mathrm{R}=\frac{\mathrm{u}^{2} \sin 2 \theta}{\mathrm{g}}$ so that $\mathrm{R}_{\max }=\frac{\mathrm{u}^{2}}{\mathrm{g}}=16 \mathrm{km}$
$\mathrm{H}_{\max }=\frac{\mathrm{u}^{2} \sin ^{2} \theta}{2 \mathrm{g}}=2 \mathrm{km}$
Standard 11
Physics