A ball thrown by one player reaches other in 2 sec. maximum height attained by ball above point of p

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3-2.Motion in Plane

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A ball thrown by one player reaches the other in $2$ sec. the maximum height attained by the ball above the point of projection will be about ....... $m$

A

$10 $

B

$7.5$

C

$5 $

D

$2.5$

Solution

(c) $\frac{{2u\sin \theta }}{g} = 2\sec $ $⇒$ $u\sin \theta = 10$

$\therefore H = \frac{{{u^2}{{\sin }^2}\theta }}{{2g}} = \frac{{100}}{{2g}} = 5m$

Standard 11

Physics

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