Gujarati
Hindi
14.Waves and Sound
normal

A string of mass $M$ and length $L$ hangs freely from a fixed point. The velocity of transverse wave along the string at a distance $'x'$ from the free end will be

A

$\sqrt {gx} $

B

$\sqrt {2gx} $

C

$2\sqrt {gx} $

D

$\sqrt {2g(L - x)} $

Solution

Let $T$ be the tension at a point distance $x$ from the free end. Then.

$T=$ (mass of $x$ meter length of string )$ \times {\rm{g}}$

$=\frac{\mathrm{M}}{\mathrm{L}} \mathrm{x} \cdot \mathrm{g}$

Velocity of transverse wave

$v=\sqrt{\frac{T}{m}}=\sqrt{\frac{M g x / L}{M / L}}=\sqrt{g x}$

Standard 11
Physics

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