- Home
- Standard 11
- Physics
11.Thermodynamics
medium
A system changes from the state $({P_1},\;{V_1})$ to $({P_2},{V_2})$ as shown in the figure. What is the work done by the system

A
$7.5 \times {10^5}\;joule$
B
$7.5 \times {10^5}\;erg$
C
$12 \times {10^5}\;joule$
D
$6 \times {10^5}\;joule$
Solution
(c) Work done = Area of $PV$ graph (here trapezium)
$ = \frac{1}{2}(1 \times {10^5} + 5 \times {10^5}) \times (5 – 1) = 12 \times {10^5}J$
Standard 11
Physics