11.Thermodynamics
medium

A system changes from the state $({P_1},\;{V_1})$ to $({P_2},{V_2})$ as shown in the figure. What is the work done by the system

A

$7.5 \times {10^5}\;joule$

B

$7.5 \times {10^5}\;erg$

C

$12 \times {10^5}\;joule$

D

$6 \times {10^5}\;joule$

Solution

(c) Work done = Area of $PV$ graph (here trapezium)

$ = \frac{1}{2}(1 \times {10^5} + 5 \times {10^5}) \times (5 – 1) = 12 \times {10^5}J$

Standard 11
Physics

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